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I was thinking of using a 5 pole Dip switch for a boost converter (04050c).The 5 resistor would replace the 100k pot. Each Dip pole would have a 20k resistor in parallel, totaling 100k.The Dip switch would be mounted upside down and with all the Dip switches in the down position (opened) all 5 resistors would be in series giving the lowest voltage output. Placing a dip switch up would close the switch, shunting a resistor. Each consecutive closed switch (up) would increment voltage.All resistors plus the 4.7k resistor should give you approximately 3.7v and with all the dip switches on plus the 4.7k, you should get 6.0vSEE ATTACHED BELOW...If you are going with 3 selection settings and using two series batteries you would not use the 04050c but perhaps a 08100w or OKR which requires a 200 ohm pot and a 220 ohm fixed resistor.Your resistor selection for minimum voltage should be 200 ohms plus the 220 ohm fixed. For max voltage output the 3rd resistance should be ZERO plus the 220 ohm fixed. Selection for the 2nd resistor would be your choice.Of course.... you may NOT want a min and max voltage so you will have to decide what voltage you would like and a little fine tuning may be necessary.As for the LED, I'll think about it and get back to you... unless someone would like to chime in here....UPDATE: I see Craig was posting the same time I was typing...
Use the 3 position selector switch you had in mind, just use the details I mentioned for a 200 ohm pot replacement.But like craig said, the LED+resistor will mess up the FB circuit.
Triple regulater schematic for 2 pole 3 position rotary switchI think something like this CK 5amp would work.http://www.ck-components.com/index.php?module=media&action=Display&cmpref=13380&lang=en&width=&height=&format=&alt=
did you order from Maplin? I used to live in Manchester back in 1998, now I live back in the Midwest USA. I guess there are plenty of places to order from these days..Let us know how it works out.