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OK so, 10k resistor -> spdt switch, one lead goes to resistor with pin 3 on the other side, middle goes to pin 4, third goes nowhere, so in one position it connects the resistor, the other, is nothing?That whole thing would also switch not just the 10k resistor, but the leads to the 100k pot in as well, which no matter what, is connected to the 10k higher up, but is only bridged with the switch in one position, am I understanding that correctly?